[SETUP] Two-Sided NewD3

Jake The Wolfie · Post Post #1 (isolation #0) » Tue Oct 06, 2020 1:21 am

I got 63 different setups. How did you get 486?

Jake The Wolfie · Post Post #3 (isolation #1) » Tue Oct 06, 2020 3:36 am

In one grid, there are 9 possible setups.

In two grids, for every one setup in the 2nd grid, there are 9 additional setups that the other grid can present.

In total, that would mean 9x9=81 (my math was incorrect) possible setups.

Jake The Wolfie · Post Post #4 (isolation #2) » Thu Oct 08, 2020 7:58 am

We should make a "Tetrahedral 2D3" where we have 4 grids, one for each of the current factions (Mafia, Werewolf, Cult, Alien).

Jake The Wolfie · Post Post #5 (isolation #3) » Wed Nov 18, 2020 5:37 pm

I determined the amount of setups is 729

For 1 cell, there are 3 possibilities:

Both Are town
#1 is WW
#2 is WW

For the other cell, the same possibilities apply, but for Mafia:

Both are town
#1 is Mafia
#2 is Mafia

This results in 3x3= 9 possibilities for any cell picked between the two tables.

Now, for any one WW Cell, the Mafia table can choose any one of it's 9 cells.
Since the WW table has 9 cells, we multiply 9x9 to get 81 possible cell combos.

But wait, that 9 from earlier joins in too, because that 9 can be applied to any of the cell pairings

81x9 = 729 possible setups!